14x+x^2=72

Solution for 14x+x^2=72 equation:

14x+x^2=72

We move all terms to the left:

14x+x^2-(72)=0

a = 1; b = 14; c = -72;
Δ = b2-4ac
Δ = 142-4·1·(-72)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-22}{2*1}=\frac{-36}{2}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+22}{2*1}=\frac{8}{2}
=4
$